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D. More Faces

Yet another problem of face degrees and leaf angles lies before us. To introduce this problem, we return to the ``tubulation'' of tetraflexagons. Let us study this type of face more carefully. The improper flexagon shown in fig. 10.8 will suffice for demonstration purposes. Suppose we leave face (1,6) and open up so that sides 1 and 4 show 10.2.

\begin{figure}\centering\begin{picture}(200,120)(0,0)
\put(0,0){\epsfxsize =200pt \epsffile{dibujos/figa08.eps}}
\end{picture}\\
Figure 10.8
\end{figure}

Side 4 will be on the inside, side 1 on the outside. We find that we can change faces a number of ways; folding the tube flat the way it was opened out gives back (1,6) if we reopen from the bottom, (1,5) if we reopen from the top. Folding the tube flat the other possible way gives the two corresponding faces (1,3) and (1,2). If we turn the tube over, so that the other end is upward, we get the faces (6,1), (5,1), (3,1) and (2,1). These are all the faces possible.

In order to deal effectively with such flexagons as this, we must correlate the operations just described with those already employed with $1-$faces. In order to obtain a system as simple and universal as possible, we maintain our former policy of minimizing class differences. Thus, since flexing has heretofore replaced one side (the lower side) by a new side, while moving the other (upper) side, we define this as flexing, for all kinds of faces. This, then, establishes which side of the flexagon is up; the sides of each face can now always be ordered. Turning over will be the operation that changes the order of the sides in the face. This ordering of the sides is, of course, distinct from the ordering of the pats. Just as turning over reverses the order of the sides, so we define rotation as reversal of the pat order. As we would naturally expect, rotation of the $2-$face meant squashing it flat another way. As for turning over, it was done in the $2-$face by rotating it $180^{\mbox{o}} $ end over end. Again as expected, this merely reversed the order of all the succeeding pats. However, flexing does not receive so simple a diagnosis as this operation.

Since we flexed from face (1,6) to a new face with sides 4 and 6, side 6 must, in the tubulation, be the side defined as the ``lower'' side. This makes sense if we think of the tubulation as a limiting case of face degrees less than $180^{\mbox{o}} $, as in Section V. To flex again, we will be required to fold together the surfaces marked 6. However, we cannot do this without moving 6 to the inside of the tube. Previously, we have been able to ``push through'' the flexagon, this operation being that which moves the flexagon from the position in which the upper side can be folded together to that in which the lower side can be folded together. This operation is inherently dependent upon the class and face degrees of the particular flexagon, therefore having no relationship to the other operations, except in that it is necessary to ``push through'' a flexagon to flex it. Thus, if a flexagon cannot be ``pushed through'' at a given face, it will not be able to leave that face except through using the side by which it arrived at it. The effect of this on the map is as if the face line were broken. A face can be pushed through only if the sum of the angles between the hinges, about the center of the flexagon, is at least $360^{\mbox{o}} $. Thus we can break map lines by building flexagons some or all of whose faces do not satisfy this requirement. In cup flexagons, for example, every map path is broken. Other interesting flexagons of this type may be made from $45^{\mbox{o}} \; - \; 45^{\mbox{o}} \; - \;
90^{\mbox{o}} $ or $30^{\mbox{o}} \; - \; 60^{\mbox{o}} \; - \; 90^{\mbox{o}} $ triangles, with two units (See fig. 10.9). In faces of degree $180^{\mbox{o}} $, such as the tubulation, the hinges are parallel, and no number of units will suffice to allow pushing through. Hence in this case the map path is always broken. If we should extend the ``pushing through'' operation to include the non-trivial case of actually cutting open the tubulation and winding it up the other way, flexing would occur unimpeded. Thus we choose to say that ``pushing through'' is impeded, rather than flexing itself. This lets flexing remain independent of the sum of the angles about the flexagon's center.

\begin{figure}\centering\begin{picture}(260,170)(0,0)
\put(0,0){\epsfxsize =260pt \epsffile{dibujos/figa09.eps}}
\end{picture}\\
Figure 10.9
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Well, if we cannot flex away from face (4,1) without turning over or cutting the flexagon, how exactly did we attain the faces that we did? In terms of the operations already known, the transition from (4,1 ) to (1,6) was clearly equivalent to turning over, flexing and turning over again. Not counting the rotation this was the same operation that brought us to (1,3). It is called a back-flex, since it is the reverse of flexing. A back-flex differs from a flex only in the side (lower or upper) that is folded together, since turning the flexagon over makes the back-flex a flex and the flex a back-flex. The operation bringing us to faces (1,5) and (1,2) must have been a back-flex, since it folded together side 4.

It may have been noticed that something is strange about faces (1,5) and (1,2). Although side 1 is technically the ``upper'' side (the side to be folded together by the next back-flex), it appears on the underside of the flexagon. Thus a subsequent back-flex will look exactly like a normal flex. Such a face, in which the ``lower'' side is on top, is described by affixing a negative sign to its face degree. Doing this is justifiable in several ways.

First, it has been seen that the hinge position used in flexing determines the face degree of the next face. The hinge position, like the face degree, can be measured in degrees, and is, in fact, the same as the face degree of the next face. Since any face in which the new side is to appear on the bottom of the flexagon opens out from the bottom, and therefore has its new hinge toward the top of the folded-together flexagon, the new hinge will be in a position between $180^{\mbox{o}} $ and $360^{\mbox{o}} $. For face degrees, however, we will use only those angles between $-180^{\mbox{o}} $ and $180^{\mbox{o}} $, so that the upside-down faces have negative face degrees. We can see that it is not sufficient to give only the face degree of a given face, since there are now four face degrees per face. For a face comprising the two sides $A$ and $B$, either side may be on top, and either side may be the ``upper'' side. Thus the form faces are $(A,B)^n,\; (A;B)^{-n},\; (B,A)^n,\; (B,A)^{-n}$10.3

There, will be four faces, related like these, whenever there is at least one. Given one of these faces, we will be able to reach other faces, made up of other sides, using flexes and rotations. Using these operations only, we can reach two and only two faces in each set of four, by following routes similar to that shown in fig. 10.10a. As we see from the figure the two related faces look exactly alike, but different sides are folded together in flexing. Doing this is equivalent to changing the flexing direction without turning the flexagon over. Thus the total number of faces breaks down into two equal families, the member of one of which can only be reached from members of the other by means of turning over. To distinguish among the various faces in the map, we mark each path with a face degree, and also indicate the ``upper'' side, by drawing an arrow from the ``lower'' to the ``upper'' side. Thus the faces made up of the two sides, $A$ and $B$, are represented as in Figure 10.10b. Turning the flexagon over, which changes face $(A,B)^n$ into face $(B,A)^n$ , is seen to reverse the direction of the arrow. The two faces that can be reached from one another by changing the flexing direction as in figure 10.10a, and which look alike, have both arrows and signs reversed. In actually using the map, we choose one in each set of four faces and mark it upon the map. The others must be figured out as needed. It helps to remember (1) that flexing backwards means that the flexing direction has been reversed, so that one travels against all the arrows and the signs of all the faces are wrong, and (2) that turning the flexagon over makes all the arrows point the wrong way or (if the flexing direction is reversed also) makes all the face degrees have the wrong sign. Thus, since in reaching faces (1,5) and (1,2) we traveled against a $1-$face arrow, the result is a $(-1)-$face with 1 rather than 5 as the upper side, although 5 is on top; the map shown in figure 10.8 could also be drawn as in figure 10.11a.

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\put(0,0){\epsfxsize =260pt \epsffile{dibujos/figa10.eps}}
\end{picture}\\
Figure 10.10
\end{figure}

\begin{figure}\centering\begin{picture}(210,140)(0,0)
\put(0,0){\epsfxsize =210pt \epsffile{dibujos/figa11.eps}}
\end{picture}\\
Figure 10.11
\end{figure}

This raises another question, which results in fairly fruitful study. Just which of the four possible faces in each set are we to mark upon the map? In all cases, we will label a given map with the members of either one of the two families of faces (but not both), thus establishing a distinction between the flexagon in a given position and the same flexagon turned over. Which family we choose is irrelevant. Between the two possible faces remaining at each position, there is no such distinction, so that they may be mixed in any way. So far, we have consistently chosen the face in each pair with the positive face degree. There is, however, another method worth considering. This method deals only with the paths on the outer edge of the map; other faces may be marked with either possible face. Considering only the outer faces, then, we find that they form a simple closed curve, enclosing the rest of the map. The arrows are placed on this curve so that they always point the same direction, clockwise or counterclockwise about the map. They are then labeled with the appropriate signs (See fig. 10.11b). The interesting thing about this method of labeling is that it gives the sign sequence signs corresponding to each outer face. These are equal to the face degrees shown. We can now, for the first time, make use of the generality with which flexing has been treated, in proving this fact. Flexing along an $0-$cut cycle without rotations shows the sub-pats corresponding to each face, with each one alone making up a pat at its face. Also, since the single-sub-pat pat alternates between the two pats, as well as inverting itself, during each flex, the sign or sum of the signs of the leaves in each single-sub-pat pat is always equal to the face degree (or the negative of the face degree; this point is irrelevant). In alternate cycles, we will travel the opposite way about the cycle. However, in changing cycles, we rotate after flexing so that the single-subpat pat occurs in the same position as it last did. This makes the face degree equal to the negative of the sum of the signs of the leaves in the single-subpat pat, rather than equal to it. Thus, if we draw the vectors the wrong way about alternate cycles, as we do when we draw them head-to-tail all about the edge of the map, the face degree will always equal the sum of the signs in the single subpat. These are the signs themselves, in the edge of the map. Q.E.D.

Since this is true, we can now easily find sign sequences for any flexagon, and, moreover, by drawing vectors all in the same direction about the edge of a map whose face degrees are unknown, and then labeling the faces with corresponding signs from a given sign sequence, we can determine the type of faces present in an unexplored map.


next up previous contents
Next: E. Negative Angles Up: Class Distinctions Previous: C. Faces   Contents
Pedro 2001-08-22